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5x^2-42x+72=0
a = 5; b = -42; c = +72;
Δ = b2-4ac
Δ = -422-4·5·72
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-18}{2*5}=\frac{24}{10} =2+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+18}{2*5}=\frac{60}{10} =6 $
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